Electrochemistry of galvanic couple in an acidic solution

AI Thread Summary
In an acidic solution of 1M HCl, gold and copper do not undergo significant electrochemical reactions because gold is more noble and does not oxidize. The hydrogen ions present cannot oxidize either metal, as they are lower on the electromotive force (emf) series. Without the presence of Au ions in the solution, there are no viable half-cell or full-cell reactions between gold and copper. The discussion highlights that copper cannot be oxidized by hydrogen, and gold will not oxidize copper either. Overall, the scenario suggests a lack of electrochemical activity between the two metals in this context.
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Homework Statement


From the perspective of corrosion...Gold and Copper II are joined together and immersed in a 1Molar HCl solution. What possible half-cell reactions and full cell reactions can occur? Which one is most likely to proceed?

Homework Equations


Half-cell potentials for
Au^{3+} + 3e^- \rightarrow Au(s) = 1.5V
Cl_2(g) + 2e^- \rightarrow 2Cl^- = 1.36V
Cu^{2+} + 2e^- \rightarrow Cu(s)=0.34V
2H^+ + 2e^- \rightarrow H_2(g)=0V

The Attempt at a Solution


The metals are exposed to hydrogen and chloride ions. Gold is the most noble and will not oxidize. The hydrogen will not oxidize copper because copper is cathodic wrt hydrogen. For the same reason, hydrogen cannot oxidize gold. Gold will oxidize copper but I don't know the hydrogen ions will steal the incoming electrons from copper and reduce to hydrogen gas.
 
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Can someone please assist me here. It's a rather simple problem but I just can't sort it through.

Hydrogen cannot oxidize gold or copper because it is lower on the emf series. Also, copper and gold cannot react because there are no Au ions in the solution (only H+ and Cl-) right? So then there aren't any half-cell/full-cell reactions?
 
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