Electron Configuration and energy levels

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Discussion Overview

The discussion revolves around the electron configuration of excited states in atoms, specifically focusing on magnesium and aluminum. Participants explore the quantum states associated with different electron configurations, including the implications of principal quantum numbers and angular momentum designators. The scope includes theoretical reasoning and homework-related inquiries.

Discussion Character

  • Homework-related
  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant states that for the excited magnesium atom, the configuration is 1s2 2s2 2p6 3p 3d, and questions how to determine the quantum states from this configuration.
  • Another participant clarifies that the principal quantum number n is 3, leading to the conclusion that l = n-1 = 2, which corresponds to a d state.
  • A different participant raises a similar question regarding an excited aluminum atom and attempts to apply the same reasoning, expressing confusion about the implications of the electron configuration.
  • One participant suggests that the excited state of magnesium involves promoting electrons from the 3s orbital to the 3p and 3d orbitals.
  • Another participant questions whether the problem requires providing quantum states for all electrons or just the outermost ones, referencing various resources for clarification.
  • One participant mentions the need to consider the configuration based on the 2S+1{L}_J labeling and discusses the implications of L-S coupling versus j-j coupling.
  • Another participant provides an example involving chlorine ions and discusses the calculation of total spin and orbital angular momentum, suggesting a method for determining possible quantum states.
  • Several participants express similar thoughts regarding the need to identify the quantum states described by n, l, m (or ml), and ms for the excited states.

Areas of Agreement / Disagreement

Participants express varying interpretations of the problem and the requirements for determining quantum states. There is no consensus on the exact approach to take, and multiple viewpoints regarding the configurations and calculations remain present throughout the discussion.

Contextual Notes

Participants highlight the importance of understanding the relationships between principal quantum numbers, angular momentum, and spin, but there are unresolved aspects regarding the application of these concepts to the specific electron configurations discussed.

Nusc
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1. Homework Statement
The electrons of a nelectronically-excited neutral magnesium atom have the coniguration 1s^2 2s^2 2p^6 3p 3d. Provide spec notation for the possible quant states of the atom as a whole


2. Homework Equations



3. The Attempt at a Solution

We neglect 1s^2 2s^2 2p^6 and only focus on 3p and 3d. I don't know what to do because we have two high energy levels to consider. If there was just one the then problem would be trivial.
 
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Okay so n = 3 therefore l = n-1 = 2.

Thus, when l = 2 we have d.

So d is our designator of choice.
 
Was the above correct? Because if I apply the same reasoning to this following problem:

an excited e-state of aluminimum atom is labelled by the config: 1s2 2s2 2p6 3s 3p2. What are the possible e-states for a atom with this config?

Here we have a choice between 3s and 3p2. n = 3 in this case therefore l = n-1 = 2 which would correspond with a d.

What the heck am I doing?
 
i don't know if i understood your problem correctly;

Mg is 1s2 2s2 2p6 3s2

when it is excited, one electron from 3s will be promoted to an empty 3p orbital.

hence:

*Mg 1s2 2s2 2p6 3s1 3p1
 
This is a good discussion of electron configuration
http://en.wikipedia.org/wiki/Electron_configuration

http://www.chemicalelements.com/show/electronconfig.html - chart

http://www.webelements.com/


Anyway, I was wondering if one has an example of what is meant by "Provide spec notation for the possible quant states of the atom as a whole"

Mg has the ground state electron configuration of 1s2 2s2 2p6 3s2, and Al has the g.s. e-config of 1s2 2s2 2p6 3s2 3p1 as indicated by Kushal.

The problem statement for an excited Mg atom states 1s2 2s2 2p6 3p 3d, so it appears one 3s electron is excited to 3p and one to 3d.


Is the problem asking for the possible quantum states described by n, l, m (or ml), ms? Does one need to provide descriptions for the n=1 and n=2 electrons, or just the outermost (valence electrons)?

See - http://hyperphysics.phy-astr.gsu.edu/hbase/hyde.html#c3

For n, what are the possible values for l, and then for l, what are the possible values for m. Then ms has two possibilities.

l is constrained such that l = 0, 1, . . . n-1,
http://hyperphysics.phy-astr.gsu.edu/hbase/quantum/hydcol.html#c2

then m = -l, -l+1, . . . , 0, 1, . . . , l-1, l (there are 2l+1 values)
http://hyperphysics.phy-astr.gsu.edu/hbase/quantum/hydazi.html#c2
http://en.wikipedia.org/wiki/Magnetic_quantum_number
 
The problem wants the configuration based on the 2S+1{L}_J labelling.
 
Here's an example: What are the poss gs of Cl+.

1s2 2s2 2p6 3s2 3p4

We need only consider the 3p4.

S = 1/2 + 1/2 + 1/2 + 1/2 : + indicates direct sum notation

So S = {0,1,2}

Since we only consider the four p electron, l =1

Therefore ml = -1,0,1

=> At least one of the spin particles must have opposite spin to the others so at least 2o f hte elctrons pair cancellin their psins. THus S= 1/2 + 1/2 = {0,1}
So the spin degeneracies are 2S+1 = {1,3}

Then L = 1 + 1 + 1 + 1 = {0,1,2,3,4}


|L-S| <= J <= L+S

Gives us a whole number of values using the 2S+1 {L}_J

Does that help?
 
I think the problem is asking for the possible quantum states described by n, l, m (or ml), ms
 
  • #10
nusc said:
I think the problem is asking for the possible quantum states described by n, l, m (or ml), ms
That is what I'm thinking.

OK, so in the example of the excited Mg, there is 1 p and 1 d electron. Then, what are the possible states for the p and for the d electron?
 
  • #11
You mean with a given p state and d state you want the orbital ang mom states?


FOr p, l =1
so ml = -1 , 0, 1

and for d, l = 2.
so ml = -2,-1 , 0, 1,2
N =3 in this case
IS that what you want?
 
  • #12
Focus on p, l =1 and d, l = 2.

J runs from |L+S| to |L-S|.

See this discussion of optical spectra.
 
  • #13
Nusc said:
The problem wants the configuration based on the 2S+1{L}_J labelling.

From that statement I will assume that we are doing L-S coupling (as opposed to j-j coupling).

Each electron has s=1/2. So what are the possible values of the total spin S?

One electron has l=1 (a p state) and the other electron has l=2 (a d state). What are the possible values of the total orbital angular momentum L?

Now, for each combination (S,L) you have (there will be a total of 6 combinations), figure out the possible values of J. Then, in each case, give the result in the notation [tex]\,^{2S+1} L_J[/tex]. For example, if the total spin is 1, L is 2 and J is 2, you have a[tex]\,^3 D_2[/tex] state.

I hope this helps
 
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