Electron Speed Calc: Solving Magnetism Problem with F=qvB

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To find the speed of an electron traveling in a circular orbit within a magnetic field, the relevant equations are F=qvB and F=ma. The challenge lies in determining the acceleration of the electron, which can be expressed as a=v²/R, where R is the radius of the orbit. By equating the magnetic force to the centripetal force, the equation qvB=ma can be rearranged to solve for the electron's speed. Given the mass, charge, magnetic field strength, and radius, the speed can be calculated using these relationships. Understanding the connection between these equations is key to solving the problem.
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An electron of mass 9.11 x 10-31 (9.11e-31) kg travels in a circular orbit within a large evacuated chamber. The orbit has a 2.0 mm radius and is perpendicular to a B-field of 0.030 T. What's the electron's speed?

For this problem, the only equation i can think to apply is F=qvB.

I know B, i know q, i need to solve for V, but how do i get F?

F =ma, but that still leaves me stuck because i don't know the acceleration of the electron...

I understand this problem and know what to do, I'm just missing something somewhere because i don't seem to have enough to solve the problem, although i know its in there. I'm just not seeing it, and need a slight prod in the right direction.
 
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I am not sure but,
F=qvb and
F=ma
so qvb=ma?
I am confuse as you are.
 
Remember that the electron travles in a circular orbit with a constant velocity, so you also have this equation

a=\frac{v^2}{R}[/color]
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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