Electron Speed Calc: Solving Magnetism Problem with F=qvB

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The discussion focuses on calculating the speed of an electron moving in a circular orbit under the influence of a magnetic field. The relevant equations are F=qvB and F=ma, where F is the force, q is the charge of the electron, v is its speed, and B is the magnetic field strength of 0.030 T. The acceleration can be expressed as a=v²/R, where R is the radius of the orbit (2.0 mm). By equating the forces, the speed of the electron can be determined using these relationships.

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An electron of mass 9.11 x 10-31 (9.11e-31) kg travels in a circular orbit within a large evacuated chamber. The orbit has a 2.0 mm radius and is perpendicular to a B-field of 0.030 T. What's the electron's speed?

For this problem, the only equation i can think to apply is F=qvB.

I know B, i know q, i need to solve for V, but how do i get F?

F =ma, but that still leaves me stuck because i don't know the acceleration of the electron...

I understand this problem and know what to do, I'm just missing something somewhere because i don't seem to have enough to solve the problem, although i know its in there. I'm just not seeing it, and need a slight prod in the right direction.
 
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I am not sure but,
F=qvb and
F=ma
so qvb=ma?
I am confuse as you are.
 
Remember that the electron travles in a circular orbit with a constant velocity, so you also have this equation

[tex]a=\frac{v^2}{R}[/tex][/color]
 

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