Electrons cannot sense electrostatic force?

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SUMMARY

The discussion centers on the inability of a digital multimeter (DMM) to detect voltage or current when connected to a DC power supply or charged capacitor in an open circuit scenario. Participants highlight that multimeters measure current flow, which is absent in this case, contrasting it with antennas that can sense electrostatic forces despite being open circuits. The conversation emphasizes the importance of understanding the differences between steady-state (DC) and changing conditions (AC, step functions, pulses), and the role of sampling rates in measurement devices. Suggestions include using a digital storage oscilloscope (DSO) for better detection of transient spikes due to its higher sample rate.

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  • Understanding of DC and AC electrical principles
  • Familiarity with digital multimeters (DMM) and their operation
  • Knowledge of digital storage oscilloscopes (DSO) and sampling rates
  • Basic concepts of capacitance and RC time constants
NEXT STEPS
  • Research the differences between DC and AC signal behavior
  • Learn about the operation and limitations of digital multimeters (DMM)
  • Explore the functionality of digital storage oscilloscopes (DSO) for transient measurements
  • Study the impact of capacitance and resistance on signal visibility in circuits
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Electronics enthusiasts, electrical engineers, and students studying circuit theory who seek to understand the nuances of measuring electrical signals in various conditions.

thomasj
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Why there is not voltage or current just for 1ms if I connect a multimeter ground to the negative terminal of a DC power supply or charged capacitor? Why electrons in measure lead and DMM device cannot sense a bulk of electrons (or lack of it)? I tried with an 5kV DC power supply too. In an antenna they sense this force and move from or to the source.
 
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thomasj said:
Why there is not voltage or current just for 1ms if I connect a multimeter ground to the negative terminal of a DC power supply or charged capacitor?
Because multimeters work on current flow and you are talking about an open circuit with zero current flow.
 
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phinds said:
Because multimeters work on current flow and you are talking about an open circuit with zero current flow.
But an antenna also an open circuit and there is current in it.
 
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thomasj said:
But an antenna also an open circuit and there is current in it.
This is a good observation and shows the danger of confusing steady state conditions (DC) with changing ones (AC /Step Functions / Pulses). EM can't be dealt with with simple, one-line statements. Even JC Maxwell needed Three Equations!
 
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sophiecentaur said:
This is a good observation and shows the danger of confusing steady state conditions (DC) with changing ones (AC /Step Functions / Pulses).
Interesting but can you explain, please? I tried to use pulse DC with a push button but no effect.
 
thomasj said:
Interesting but can you explain, please? I tried to use pulse DC with a push button but no effect.
The title of your thread refers to Electrostatic Forces. When the forces are not Static, things are different. The reason that your DMM recorded nothing will be a combination of factors. Firstly, a Digital Analogue Converter (the heart of a DMM) takes samples and gets an average over its sample interval. The total charge that passes with an experiment like yours will depend on the Capacitance of the apparatus. The peak current could be fairly high (easily detectable by your DMM) but the average may be very small. It's the sort of thing that a 'clunky' analogue meter might show you by a tiny twitch of a needle. (Newer doesn't always mean better. :wink:)
 
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sophiecentaur said:
... but the average may be very small. It's the sort of thing that a 'clunky' analogue meter might show you by a tiny twitch of a needle. (Newer doesn't always mean better. :wink:)
Thanks, I suspect this. And if I would use a DSO instead? Sample rate of that device is high enough I guess. Shorter time period's average could be better here.
 
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thomasj said:
nd if I would use a DSO instead? Sample rate of that device is high enough I guess.
Depending on the capacitance of that wire, picoseconds or nanoseconds might be needed to see the spike.
 
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anorlunda said:
Depending on the capacitance of that wire, picoseconds or nanoseconds might be needed to see the spike.
The series R would be relevant, wouldn't it? RC time constant would be longer
 
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sophiecentaur said:
The series R would be relevant, wouldn't it? RC time constant would be longer
The way the OP stated it, is is the R of a short piece of wire.

But time constant alone does not make it visible. It is area under the curve, i.e. energy, that makes the difference between visually visible or invisible pulses.
 
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anorlunda said:
The way the OP stated it, is is the R of a short piece of wire.

Again, there is no circuit diagram to enable us all to be discussing the same situation. I assumed that a meter was in series.
 

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