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Electrostatic fields in vacuum

  1. Nov 23, 2012 #1
    1. The problem statement, all variables and given/known data

    An atom H has a charge +q (=proton) and -q(=electron). q = 1,6.10^-19.
    The electron is circeling around the proton at r distance r = 0,53.10^-10m.

    What is the force as a result of the electrostatic interaction between the proton and electron

    2. Relevant equations



    3. The attempt at a solution

    F = (1/(4 x pi x epsilon 0)) x ((q1.q2) / r^2)

    1/(4 x pi x epsilon 0 = 9 x 10^9 = k
    q1 = 1,6.10^-19
    q2 = -1,6.10^-19
    r = 0,53.10^-10m

    F = k . q.-q/ r^2 = k. -q^2/r^2
    F = (9 x 10^9* 1,6.10^-19* -1,6.10^-19) / 0,53.10^-10*0,53.10^-10
    F = -2,3 .10^-28/2,8.10^21 = - 8,2.10^-8

    Is this correct?
     
  2. jcsd
  3. Nov 23, 2012 #2
    Looks fine to me.

    You don't need a minus sign for the charge, since you're working out the magnitude of the force.
     
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