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plover
Homework Helper
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Or for those whose tastes run to notation sadism:
[tex]- \lim_{0\rightarrow0} 0![/tex]
Last edited:
Zurtex said:Strictly speaking [itex]0^0[/itex] is not defined. As:
[tex]x^0 = \left( x^1 \right) \left( x^{-1} \right)[/tex]
Therefore:
[tex]x^0 = \frac{x}{x}[/tex]
Which means [itex]x^0 = 1[/itex] when [itex]x \neq 0[/itex]
Gunni said:There's another fun variation on this theme where you line up all the numbers from one to nine in threes and are supposed to make them add up to six by adding only plus, minus, division, multiplication, root and power signs (whole powers and roots, no logs!). You can also use ( and ) (forgot what they're called).
Like this:
Code:1 1 1 = 6 2 2 2 = 6 3 3 3 = 6 4 4 4 = 6 5 5 5 = 6 6 6 6 = 6 7 7 7 = 6 8 8 8 = 6 9 9 9 = 6
For example (I hope I'm not ruining anything for anyone here ):
6 + 6 - 6 = 6
Have fun.
NoNose said:Hi
First: Sorry if my english isn´t correct or couldn´t be understand, but i´m trying to.
Without to resume the discussion, if factorial and bases are elemental math, i´m thinking i´ve found a solution for the problem down this text for all positive and negative real numbers and the 0:
[tex]\left( \left( x^2 \right) ^0 + \left( x^2 \right) ^0 + \left( x^2 \right) ^0 \right) ! =6[/tex]
Njorl said:10 (44-4)/4
I had to use one "44". Is there a way to get 10 without resorting to this?
Njorl
arildno said:[tex]9+\frac{9}{9}=20_{(base 5)}[/tex]