kcodon
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Ok let me reword my question. I am trying to determine whether the EM wave itself can be thought of as simply a ripple in the EM field of the initial source. This would explain why a lesser force is felt at a distance (EM field is weaker i.e. 1/d^2 and EM radiation is less probable/weaker by 1/r^2...they are equivalent), and seems a much simpler view of things. Or is it that the EM radiation is separate from the field itself. This is why I asked the following:A test charge some distance away, won't feel the effect of a given oscillation instantly - this is a reflection of the fact that EM waves have a finite speed.
Yes, photon flux is proportional to irradiance - so two charges sitting in points of space with equal irradiance will feel the same magnitude of force.
In other words, is the EM radiation a separate field, or the same field as that of the source (changing as the sources does). If so what evidence for this is there? Do you understand my question? Sorry I'm just struggling to put it into words, even though in my head the concept is so simpleHowever when you say it will cause a test charge to feel a force, I take it this is not due to the actual alternating electric field around the dipole is it? I mean at some distance close to the rotating dipole, the test charge will be in its electric field, and will thus feel force not due to the EM. Does this mean that when the test charge is far away, outside of the influence of the electric field from the rotating dipole, that it will feel a force from the EM radiation?
So this implies that the force felt by one photon (i.e. same irradiance) will get weaker as radius gets bigger? Kind of goes with what I was saying above.Yes, photon flux is proportional to irradiance - so two charges sitting in points of space with equal irradiance will feel the same magnitude of force.
Ok this is interesting. Somehow the photon gives up energy to cause the force, yet travels away with the same energy? Or in the case of the transparent medium, is this to do with the resonance in the phonons etc, so energy is still conserved?Photons do not have to be absorbed to exert a force, for example a wave transmitted through a transparent medium, will cause that medium to polarise momentarily, thus the medium experiences a force, even though the photon continues on its merry way.
Ok I looked up Fourier analysis and it looks a bit over my head...but are you saying that the shape of the field (whatever it may be) of a linearly accelerating partice, can be represented as the sum of other fields that area sinusoidal? That seems like cheating almost, if you know what I mean. Mind you how else you manage to physically get a sinusoidally oscillating EM field from a linearly accelerating charge I have no idea...if anyone else does it would be much appreciated if you shared it.An oscillating field would not be caused by something like this, the field would not be sinusoidal, it would be some other shape (Gaussian maybe). Using Fourier analysis, we can decompose any waveform into its spectrum, so while the total field may not strictly be oscillatory, we can describe any field as a sum of oscillatory components.
Hmmm I have just read some stuff from other posts, and it looks pretty confusing as to why accelerating charges emit radiation:
https://www.physicsforums.com/showthread.php?t=183074"
(I like the idea stated here by Andrew Mason that charges can only be accelerated by an EM force etc)
And then also it gets confusing with relativity and gravity etc:
https://www.physicsforums.com/showthread.php?t=160533"
I said uniform velocity relative to the (accelerating) charge...so you are accelerating also...not an inertial frame.No! Any inertial frame of reference will "see" the charge being accelerated.
Thanks for the heads up...I looked into polarisation and you're right it wasn't too challengingPolarisation is not complicated, it is just the direction the electric field pushes the hypothetical test charge. A rotating polarisation will cause the test charge to move in a circular (or corkscrew) motion.
I was considering starting a new thread about accelerating charges and radiation, however it doesn't actually look like anyone knows, so I think I'll leave it. Thinking about it you can kind of intuitively see how the strength of the electric field changes...it "builds up" in the direction of acceleration (I'm just guessing here), but not how a sinusoid is generated.
Thanks again for your help Claude,
Kcodon
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