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Empiric formula

  1. Feb 6, 2005 #1
    I can't solve this: 1.63 g crom oxid gave 1.12 g crom during analysis. Calculate the empiric forumla of crom oxid.

    % Cr = 1.12 : 1.63 * 100 = 68.7 %
    % O = 100 - 68.7 = 31.3 %
    Cr_xO_y
    x:y = 68.7 : Cr : 31.3 : O
    = 68.7 : 52 : 31.3 : 16
    = 1.32 : 1.96
    = 1 : 1
    CrO
    Which is completly wrong.
     
  2. jcsd
  3. Feb 6, 2005 #2

    chem_tr

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    Science Advisor
    Gold Member

    Hello, try this: 1.32 and 1.96 can be further divided to give 1 and 1.485; this means that approximately 1:1.5 ratio is present. This is the same as 2 to 3, I mean Cr2O3

    To sum up, dividing further to obtain a 1 in the series is the most important step here.
     
  4. Feb 6, 2005 #3
    Ahh! I understand!
     
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