Empirical Formula for Magnesium Oxide

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The empirical formula for magnesium oxide is MgO, which results from the combination of magnesium in a +2 oxidation state and oxygen in a -2 oxidation state to form a neutral compound. While magnesium oxide can also exist in other forms like Mg2O2 or Mg3O3, the simplest ratio of magnesium to oxygen is 1:1, leading to the empirical formula MgO. Understanding this concept is crucial, as it illustrates the relationship between the elements in a compound. The discussion emphasizes the need for clarity on empirical formulas, especially for students new to the topic. Overall, grasping the basic principles of oxidation states and molecular neutrality is essential for understanding magnesium oxide's empirical formula.
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I'm currently trying to understand the concept that my chemistry teacher wants me to figure out. We are not doing stoichiometry. We haven't even gotten the definition for it. Now I need to find the empirical formula for magnesium Oxide.

My friends kept telling me (MgO) Which I didnt fully understand but I wanted to know if anyone would be able to help me because I'm really in a pickle right now.

I can give you more information if you would be so kind to contact me ASAP.

*Amanda
 
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Emprical formula - http://www.towson.edu/~ladon/empiric.html

Magnesium Oxide - http://en.wikipedia.org/wiki/Magnesium_oxide

Now why is the formula MgO? Magnesium exists in an oxidation state of +2 and oxygen -2. To make a neutral molecule one magnesium must combine with one oxygen. It talkes about empirical formulas since magnesium oxide can exist as a crystal and could have formulas such as Mg2O2, Mg3O3, etc
 
I've seen those sites but thank you for responding. Its rather fuzzy of an idea. And I'm still moderatly confused.
 

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