1. The problem statement, all variables and given/known data 2. Relevant equations V = L di/dt Energy = V*I*t 3. The attempt at a solution First we find out V across L This V will be there only for 1st 2 seconds as after that there is no change in current. So V(across L) is L * di/dt = 2 * 6/2 = 6V equation 1 Now Current is a function of time so it's i = 3t equation 2 So to get Energy we use integration. Energy = integration of V*I*dt where limits are 0 to 2 So now using equation 1 and 2 we get Energy = integration of 6 * 3t dt from limits 0 to 2 so this is 18 t2/2 t varies from 0 to 2 So this is 9 (4) = 36 which is not in the options. Where am I wrong. I even tried other formula of Energy = 1/2 * L * I2 But this gives 24 I'm getting different answer for different formula but neither answer matches options. Where am I wrong?