Energy and Momentum Problem HELP

  • Thread starter Thread starter Givhaa24
  • Start date Start date
  • Tags Tags
    Energy Momentum
AI Thread Summary
To solve the energy and momentum problem, first calculate the force exerted by Brutus while lifting the 260 kg weights, which is equal to the weight of the mass (force = mass x gravity). The work done while holding the weights above his head is calculated using the formula W = Fd, where F is the force and d is the distance (2.50 m). When lowering the weights, the work done is also the same amount but in the opposite direction, resulting in the same Joules. Finally, to find the power developed, divide the total work done by the time taken (2.4 s) using the formula P = W/t. This approach provides a clear understanding of the work and power involved in Brutus's weightlifting.
Givhaa24
Messages
1
Reaction score
0
Energy and Momentum Problem...HELP!

Homework Statement



Brutus, a champion weightlifter, raises 260 kg of weights a distance of 2.50 m.
(b) How much work is done by Brutus holding the weights above his head in Joules?
(c) How much work is done by Brutus lowering them back to the ground in Joules?
(e) If Brutus completes the lift in 2.4 s, how much power is developed?


Homework Equations


W=FdCos
P=W/t


The Attempt at a Solution

 
Physics news on Phys.org


you know the mass. and the distance that the mass is lifted.
so calculate the force of the mass
then calculate the work done
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top