Energy Changes of Cyclist: X to Y

  • Thread starter Thread starter Cheesus128
  • Start date Start date
  • Tags Tags
    Energy
AI Thread Summary
The discussion focuses on the energy changes experienced by a cyclist traveling downhill, applying brakes to stop. Participants analyze various energy transformations, including kinetic energy, gravitational potential energy, and internal heat. The cyclist's motion involves converting gravitational potential energy into kinetic energy and then into internal heat upon braking. The conversation also touches on the urgency of preparing for an upcoming IGCSE exam. Ultimately, the key energy transformation discussed is the conversion of kinetic energy to internal heat as the cyclist stops.
Cheesus128
Messages
22
Reaction score
0
Sorry for brief formulation but have no time.

Cyclist travels down hill, no pedalling.
Applies breaks at X and stops at Y.

Which energy changes have taken place between X and Y?

A. Kinetic --> internal (Heat) ---> Grav potential
B. Kinetic --> Grav Potential --> Internal heat
C. Grav Potenial --> Internal (heat) ---> Kinetic.
D. Grav Potential --> Kinetic ---> Inetnal Heat

Thank you!
 
Physics news on Phys.org
lol are you using your blackberry during a test?
 
Hahaha no I am just doing a Paper and don't have the marking scheme.
My IGCSE is tomorrow though.
So maybe that's a good idea ;D
Anyway know the answer?
 
Ya but i don't think I am suposed to say
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Can heat flow into a body without increasing the mean kinetic energy?
Replies
1
Views
1K
Potential Energy and raising a satellite from Earth into a Circular Orbit
Replies
5
Views
2K
Thermodynamics: Internal Energy, Heat and Work Problem
Replies
1
Views
2K
Why is/is-not energy conserved in these scenarios?
Replies
14
Views
2K
Is potential energy defined only for internal conservative forces?
Replies
15
Views
1K
Resistance force changing the velocity of an object
Replies
8
Views
1K
Oscillation of free surface of water in parallelepiped container
Replies
13
Views
2K
Find elastic energy in the compressed spring.
Replies
12
Views
3K
Kinetic/Potential Energy and Work help
Replies
3
Views
2K
How Does Potential Energy Dissipation Affect Temperature in a Metal Cube?
Replies
9
Views
1K

Hot Threads

Recent Insights

Back
Top