Energy Dissipation in Horseracing

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SUMMARY

The discussion focuses on calculating energy dissipation in horseracing using the kinetic energy formula, specifically for two horses racing 1320 feet. Horse A completed the race in 72 seconds, while Horse B finished in 71 seconds. The kinetic energy is calculated using the formula Kinetic Energy = 1/2mv², where 'm' is the mass of the horse (1200 pounds) and 'v' is the average velocity over each 440-foot segment. This approach allows for a detailed analysis of energy expenditure during the race.

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panz
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Hi,

First time posting. I have some scattered notes that I found on applying physics to horseracing. One of the notes talked about the energy dissipation of each horse's prior races but no formula was given. Could anybody show me how to calculate the energy dissipation for each horse in the following example; assuming each horse is 10 feet long and each weighing 1200 pounds. They will race 1320 feet and the times listed below are how long it takes each horse to run the first 440 feet, the second 440 feet and the third 440 feet and the final time.

Horse A 23 seconds, 24 seconds 25 seconds total 72 seconds
Horse B 24 seconds, 23 seconds 24 seconds total 71 seconds

Thanks for any help you can give me.
 
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Well I suppose the simplest way I can think of doing it is assuming an average velocity over each section and using the following energy equation:

Kinetic Energy = 1/2mv2

Where m = mass of horse, v = average velocity.

This will give you the kinetic energy of each horse during each section of the race.
 

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