Energy flow into and around a slowly charging capacitor

In summary, the energy flow vector field near and far from the slowly charging capacitor is S. Energy is drawn from the battery and flows into the slowly charging capacitor. Energy is lost to space in the form of I2R loss and electron drift. Energy is eventually stored in the capacitor.
  • #1
Spinnor
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Picture a charging capactor, you know the E field, and the induced B field, the energy flow is just EXB.

capacitor.gif


Please describe for me in rough terms the energy flow vector field near and far from the slowly charging capacitor? The flow of energy must ultimately come from the source of energy that charges the capacitor, say a battery? Has anyone ever seen an image of such a flow of energy for this system? Can you roughly sketch what it should look like? Do you simply draw lines of S from the battery to the entrance of the gap of the capacitor? Let the only resistance of the circuit be the internal resistance of the battery. Feynman goes into this here,

http://www.feynmanlectures.caltech.edu/II_27.html

Thanks!

Edit, where in space and time can one safely say that the field S should be zero?
 
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  • #2
There was a recent response in the Forum showing a Poynting Vector spreading out from the battery and converging on the capacitor.
As an engineer, however, I prefer to see circuits such as this analysed as transmission line problems. When treated in this way, there is oscillation when the battery is connected, and then conditions gradually settle down to zero current at full battery voltage. The oscillations are absorbed by the battery resistance.
 
  • #4
The moment you throw the switch, the capacitor looks like a short circuit to the battery, so a slowly charging capacitor would infer a high resistance, or high inductance in series with the cap.

If there is no significant inductance in the circuit then some of the energy will be dissipated in I2R loss. If the resistance is small then some of the energy will be electromagnetically radiated into space. Either way at least half the energy drawn from the battery will not get stored in the capacitor.
 
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  • #5
I have not thought deeply about this, but feel that the answer may lie in thinking of the circuit as a fully 3D object.

Between the capacitor plates, sure that's where E and B are pointing, but outside the plates you have a fringing field and E has a radial component, which must mean S must have an axial component (the axis of the cylindrical capacitor plates in the diagram). That's a good starting point to retracing the origin of the vector.

There is another subtlety here. You said "slowly" charge the capacitor. This implies a quasi-static approximation where higher order field effects (e.g. secondary E and B fields). In this approximation I don't expect any far field energy flow, since far field energy flow would be radiative (which requires the secondary and higher field effects). Maybe I misunderstood this part...
 
  • #6
David Lewis said:
Either way at least half the energy drawn from the battery will not get stored in the capacitor.

Is that easy to show? I guess a solid state device could control the current to minimize energy lost to space though you say it is going to be at least half.

Still would be interesting to see the energy flow pattern from the energy source to the capacitor. Probably just need a simple specific example.

Thanks!
 
  • #7
It's not easy to show. The sources of parasitic losses in a pure capacitance circuit are not obvious and, due to energy conservation laws, unavoidable.
 
  • #8
So there will be loses. I am still interested in the flow from the source to the sink. Consider the following specific example,

upload_2016-8-6_13-51-29.png


We initially have a charged and a uncharged capacitor with wires that nearly touch. Then we span the two gaps with two resistors R. Energy will flow from one capacitor to the other and energy will also flow to infinity. If we were to carefully account for the electric and magnetic fields should we be able to plot power flow to and from the capacitors and also the power flow towards infinity?

Thanks!
 

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  • #9
Electron drift moving at constant speed is impeded by loss resistance.
Whereas accelerating electrons that generate an EM wave are impeded
by both loss resistance and radiation resistance.

We had a discussion concerning energy lost when one capacitor charges another in the thread Potential Difference. across capacitors in the General Physics forum, which I think you will find helpful.
 
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1. How does energy flow into a slowly charging capacitor?

Energy flows into a slowly charging capacitor through an external voltage source, such as a battery or power supply. As the capacitor charges, it stores electrical energy in the form of an electric field between its two plates.

2. What is the role of resistance in the energy flow into a slowly charging capacitor?

Resistance plays a crucial role in the energy flow into a slowly charging capacitor. It limits the rate at which the capacitor can charge, as it slows down the flow of current from the external source into the capacitor. This is why a resistor is often placed in series with the capacitor in a charging circuit.

3. How does the energy flow around a slowly charging capacitor?

The energy flows around a slowly charging capacitor in the form of an electric current. As the capacitor charges, the electric field between its plates increases, causing a flow of electrons from one plate to the other. This creates a current that flows around the circuit, including through the capacitor.

4. What happens to the energy flow when a capacitor is fully charged?

When a capacitor is fully charged, the energy flow stops. This is because the capacitor has reached its maximum capacity to store electrical energy. At this point, the capacitor acts as an open circuit and prevents any further flow of current.

5. How does the energy flow change as the capacitor charges more quickly?

The energy flow into and around a capacitor changes as the capacitor charges more quickly. With a faster charging rate, the energy flow into the capacitor will be greater, and the capacitor will reach its maximum charge more quickly. The energy flow around the capacitor will also be greater, as there will be a higher current flowing through the circuit. This can result in a larger voltage drop across the resistor, leading to a quicker charging time.

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