Energy-height graph of a ball falling through a viscous fluid

AI Thread Summary
The discussion focuses on drawing the energy-time graph for a ball falling through a viscous fluid, specifically addressing the kinetic energy (KE) and gravitational potential energy (GPE) graphs. The GPE graph is expected to be a straight line with a negative gradient, while the KE graph starts at zero, curves upwards, and plateaus at terminal velocity reached at height H/2. A key point of contention is the shape of the KE curve before reaching H/2, with a suggestion that it should be concave upwards for H<1 and convex until H/2, indicating a point of inflection at H=1. This raises questions about the relationship between velocity and kinetic energy, as the KE formula suggests a different graph shape. The discussion emphasizes the need for clarity in the problem statement regarding the energy-height graph.
tatata
Messages
2
Reaction score
0

Homework Statement



A ball falls from rest through a viscous fluid in a tall beaker of height H. It reaches terminal velocity at height H/2. Draw the energy-time graph for kinetic energy and gravitational potential energy on the same axes.

Homework Equations



F=6πηrv

The Attempt at a Solution



The graph of GPE should be a straight line with a negative gradient, cutting the y-axis at mgh and the x-axis at H.

The graph of KE should start from 0, then curve upwards before plateauing at H/2.
The problem is the shape of the curve before H/2. My teacher says that the graph should be concave upwards for H<1, then convex until H/2, meaning there is a point of inflection at H=1.

I think this is rather strange as the v-t graph is convex all the way until terminal velocity is attained. KE is 1/2mv^2, so shouldn't the graph be a straight line, if not convex all the way?
 
Physics news on Phys.org
The problem statement should read "Draw the energy-HEIGHT graph for kinetic energy and gravitational potential energy on the same axes."
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top