Energy into a rigid container>Find T2 and P2

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The discussion centers on calculating the final temperature (T2) and pressure (P2) of air in a rigid, insulated container after a fan draws 1.5 kW of electricity for 30 minutes. The initial conditions are 1 atm pressure and 27 degrees Celsius temperature, with a total energy input of 2700.8 kJ. The user notes that since the container is insulated, there is no heat exchange (Q = 0), and thus the work done by the system is negative. The main challenge is connecting the energy input to changes in temperature and pressure using the ideal gas law and other relevant equations. Participants are encouraged to provide guidance on how to relate energy changes to temperature and pressure in this scenario.
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Homework Statement


A Fan draws electricity at a rate of 1.5kW.
The fan is in a well insulated rigid container of air with volume 60 m^3.
Initial pressure and Initial Volume are: P1 = 1 atm, T1 = 27 degrees C.
After 30 minutes, assume Ideal Gas behavior, determine the final Temp and final Pressure.

Homework Equations



ΔE = Q - W
PV=nRT
ΔU=mc(T2-T1)?

The Attempt at a Solution



I calculated the energy into the system to be 2700.8 kJ after 30 minutes. Since there is no ΔKE or ΔPE, ΔE = ΔU = 2700.8 kJ. Since it is well insulated, Q = 0. So W = -2700.8 kJ.

I am having trouble linking the relationship between Energy and Temperature/Volume. I am not sure what other equations to use, so I am making no progress on this problem.
 
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Does anyone have some advice. I will take anything that points me in the right direction, lol.
 

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