Energy levels shifts in a time-varying electric field

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SUMMARY

The discussion centers on energy level shifts in a time-varying electric field, specifically involving two levels of the same parity (##E_1## and ##E_2##) and a third level of opposite parity. The participant explores the implications of using a laser on resonance with the transition from ##E_2## to the opposite parity level, noting that the laser frequency corresponds to the energy difference ##E##. It is established that the effective location of the energy levels will shift due to the Rabi frequency (##\Omega##) of the laser, resulting in a shift of ##\frac{\Omega^2}{4(E_2-E_1)}##. The analysis confirms that this shift occurs under the condition that ##\Omega << E_2 - E_1##.

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BillKet
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Hello! I have 2 levels of the same parity with energies ##E_1 < E_2##, and another level of opposite parity a distance ##E## from the ##E_2##. I also have that ##E_2 - E_1 << E##. I have a laser on resonance (I am trying to scan along the resonance and find it) with the transition from ##E_2## to the other level (so the laser frequency corresponds to ##E##). Does this mean that while I am scanning the transition of interest, the laser will also couple ##E_1## with the other level and hence shift the effective location of the 2 levels? Basically by this effect, the opposite parity level will be shifted by ##\frac{\Omega^2}{4(E_2-E_1)}##, where ##\Omega## is the Rabi frequency of the laser. So the frequency I am measuring in practice will be shifted. Similarly, if I measure the transition from ##E_1## to ##E##, I will have the exactly same shift, but in opposite direction. Is this right or am I missunderstanding my system? Thank you!
 
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Your analysis looks right to me, in the limit of ##\Omega << E_2 - E_1##.
 

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