A Energy levels shifts in a time-varying electric field

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In a system with two energy levels of the same parity and one of opposite parity, a laser tuned to the transition between the higher level and the opposite parity level can induce coupling effects. As the laser scans the resonance, it can also couple the lower level with the opposite parity level, resulting in an effective shift of the energy levels. This shift is quantified by the formula ##\frac{\Omega^2}{4(E_2-E_1)}##, where ##\Omega## is the Rabi frequency. Additionally, measuring the transition from the lower level to the opposite parity level will yield a similar shift in the opposite direction. The analysis confirms that these effects are valid under the condition that ##\Omega << E_2 - E_1##.
BillKet
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Hello! I have 2 levels of the same parity with energies ##E_1 < E_2##, and another level of opposite parity a distance ##E## from the ##E_2##. I also have that ##E_2 - E_1 << E##. I have a laser on resonance (I am trying to scan along the resonance and find it) with the transition from ##E_2## to the other level (so the laser frequency corresponds to ##E##). Does this mean that while I am scanning the transition of interest, the laser will also couple ##E_1## with the other level and hence shift the effective location of the 2 levels? Basically by this effect, the opposite parity level will be shifted by ##\frac{\Omega^2}{4(E_2-E_1)}##, where ##\Omega## is the Rabi frequency of the laser. So the frequency I am measuring in practice will be shifted. Similarly, if I measure the transition from ##E_1## to ##E##, I will have the exactly same shift, but in opposite direction. Is this right or am I missunderstanding my system? Thank you!
 
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Your analysis looks right to me, in the limit of ##\Omega << E_2 - E_1##.
 
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