Energy Loss in Head on Collision of Two Cars w/Same Speed and Mass

AI Thread Summary
In a head-on collision of two railroad cars, each weighing 7,000 kg and traveling at 90 km/h, the mechanical energy lost is calculated using kinetic energy formulas. Initially, the kinetic energy was incorrectly calculated due to the use of km/h instead of m/s. After converting the speed to 25 m/s, the correct kinetic energy is found to be 2.1875 million joules for one car, leading to a total energy loss of approximately 4 million joules. The discrepancy in the initial calculation was clarified by addressing unit conversion. The final answer aligns with the book's solution, confirming the energy lost in the collision.
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Homework Statement



Two railroad cars, each with a mass of 7,000kg and traveling at 90 km/h collide head on and come to rest. How much mechanical energy is lost in this collision?

Homework Equations



KE=\frac{1}{2}mv^2

The Attempt at a Solution



KE=\frac{1}{2}(7000)(90)^2=2.835*10^7

Mechanical energy = KE+PE. PE = 0.

Energy lost = 2KE or 5.67*10^7

Book answer is 4*10^6

Where am I going wrong? Thanks..
 
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If your result is in joules, the velocity units of km/h is not helping.
 
Convert the speed to standard units of m/s.
 
Ahh... So 90 km/h = 25 m/s.

\frac{1}{2}(7000)(25)^2=2.1875*10^6 => 2.1875*10^6(2) = 4.375*10^6 => 4*10^6

Thanks!
 
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