Energy necessary to put something in orbit

  • Thread starter Thread starter undividable
  • Start date Start date
  • Tags Tags
    Energy Orbit
AI Thread Summary
To determine the energy necessary to put an object in orbit around the Earth, one must consider both the initial kinetic energy required for orbital velocity and the gravitational potential energy at the desired altitude. The discussion highlights confusion regarding the initial kinetic energy (Ki) of an object at rest, emphasizing that Ki should reflect the velocity needed for orbit. Additionally, participants note the ambiguity in the question's wording, particularly regarding the definition of "at rest" and the lack of specified parameters like orbital radius. Clarification on these points is deemed essential for accurately calculating the required energy. Understanding the relationship between initial, added, and final energy is crucial for solving the problem effectively.
undividable
Messages
23
Reaction score
0

Homework Statement


Object A is at rest relative to the Earth and we want to put it in orbit around the earth, how much energy is necessary to do so?

Homework Equations



Ki+Ui=Kf+Uf+energy input[/B]

The Attempt at a Solution



what i don't understand is, if the body is at rest, Ki=0, but don't we need a certain inicial velocity to put it in orbit? So shouldn't Ki have a value?[/B]
 
Physics news on Phys.org
I think that is exactly what the question requires you to answer. That is how much initial kinetic energy is required to put the rocket in orbit around the Earth at a certain distance above the surface of the earth.
 
Point 1: If Ki+Ui is the initial total energy of the object while at rest with respect to the Earth and Kf+Uf is the final energy of the object in orbit, Then why would you add energy to the total final energy to get the total initial energy?

Point 2: Just relating initial energy, added energy, and final energy is not enough, you also need to know how to determine what final energy is needed for the orbiting object.
 
undividable said:
Object A is at rest relative to the Earth and we want to put it in orbit around the earth, how much energy is necessary to do so?
Is that the whole question? It is very poorly worded.
What does at rest relative to the Earth mean? I could read that as including Earth's rotation, so at the right radius it would be in geostationary orbit already.
It does not say the radius is to be unchanged.
It should provide some variable in terms of which you can express the answer; that could be the height (from Earth's centre), or its GPE, or ...?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top