Energy of a car going up a hill

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To calculate the energy required for a car to accelerate uphill, both kinetic and potential energy must be considered. The kinetic energy (KE) is calculated using the formula KE=1/2m(V2^2-V1^2), resulting in 374,922 J for the speed increase from 15 km/h to 75 km/h. Additionally, potential energy (PE) due to the vertical rise of 55 m is calculated using PE=mgh. The total energy required combines both kinetic and potential energy, confirming the need to include the height in the overall energy calculation. Understanding both energy types is essential for accurate results in this scenario.
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Not using homework template due to originally being posted in a different forum.
find the energy of a required to accelerate a 1800kg car from 15 km/h to 75km/h an up hill road with a vertical rise of 55m

KE=1/2m(V22-V12)

KE=1/2(1800)(20.832-4.162)

KE=1/2(1800)(433.88-17.30)

KE=1/2(1800)(416.58)

KE=1/2(749844)

KE=374922 J

I'm wondering if I'am on the right track, no sure how to bring the rise into the problem.
 
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anthonyk2013 said:
I'm wondering if I'am on the right track, no sure how to bring the rise into the problem.

+ mgh
 
KE=1/2m(V22-V12)+mgh ?
 
Energy = Kinetic energy + Potential energy

Potential energy = mgh
 
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