Energy released in nuclear fission problem

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SUMMARY

The discussion focuses on calculating the energy released during nuclear fission, specifically addressing a problem where the work done (W) is determined to be 975 MeV. The participants analyze the splitting of a nucleus into two smaller particles, each with half the charge (Q/2) and half the volume (V/2). They conclude that the volume is conserved during the fission process, leading to a calculated change in work (ΔW) of 360 MeV.

PREREQUISITES
  • Nuclear fission principles
  • Understanding of energy units in MeV (Mega-electronvolts)
  • Basic concepts of volume and density in nuclear physics
  • Mathematical manipulation of physical equations
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  • Explore detailed calculations of energy release in various fission reactions
  • Learn about the role of nuclear density in fission processes
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Homework Statement



21b10ci.png


Homework Equations





The Attempt at a Solution



(a) Shown.

(b) W = 975 MeV

(c) Initially nucleus has volume V. Splits into two smaller particles each with charge Q/2, and volume V/2. So for each particle, Q/2 and R*(1/2)1/3

So, W' ~ 2 * [(0.5)2/(0.5)1/3] = (0.5)2/3

ΔW = 360 MeV


I'm not sure if the volume of each is halved or not by their phrasing..
 
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Both spheres get V/2, right. The density of nuclei is roughly constant, so volume is conserved in nuclear reactions.
 

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