Energy required to move an object to an altitude twice the radius of Earth

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SUMMARY

The energy required to move a 1,000-kg object from the Earth's surface to an altitude twice the Earth's radius is calculated using the gravitational potential energy formula U = - G Me m / r. The correct approach involves finding the difference in potential energy between the surface and the altitude of 3r, not 2r, as the problem specifies an altitude above the Earth's surface. The final calculated energy is approximately 3.1 x 1010 J, aligning with the correct interpretation of the problem.

PREREQUISITES
  • Understanding of gravitational potential energy
  • Familiarity with the gravitational constant (G)
  • Knowledge of Earth's mass (Me) and radius (r)
  • Basic algebra for manipulating equations
NEXT STEPS
  • Review gravitational potential energy calculations in physics
  • Study the implications of altitude on gravitational force
  • Learn about the gravitational constant (G) and its applications
  • Explore potential energy differences in multi-body systems
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Students studying physics, particularly those focused on mechanics and gravitational forces, as well as educators looking for examples of potential energy calculations.

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Homework Statement


How much energy is required to move a 1 000-kg object
from the Earth’s surface to an altitude twice the Earth’s
radius?


Homework Equations


U = - G Me m / r


The Attempt at a Solution



I'm just using the above equation with 2r (twice the radius) and get 3.1 x 10e10 J, but the book says different...

Any help?? Thanks!
 
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Plugging in a certain radius just tells you the potential energy an object has at that distance from the center. The question is asking you how much energy it takes to move from 1 radius (the surface) to another radius. So you need to find a difference in potential energy.

In this case, you need to find the potential energy difference between the mass at the surface and at that 2r altitude. This must be the energy required to bring it from the surface to the high up distance.
 
actually, I think I figured it out. The problem is somewhat bad worded and I believe it can confuse people. It says an ALTITUDE twice the radius of Earth, which means two times that distance ONCE the object has left the Earth, so actually it would be 3r... right?

I guess it's right, I got the correct answer ;) thanks for the help!
 

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