Energy uncertainty of an atom in an excited state

AI Thread Summary
The discussion revolves around calculating the energy uncertainty of a sodium (Na) atom in an excited state that lasts for 1.6 x 10^-8 seconds before transitioning to the ground state and emitting a photon of 2.105 eV. Participants express confusion about applying the uncertainty principle, particularly the relationship between energy uncertainty and time uncertainty. One user suggests using the equation ΔE > ħ/(2Δt) but questions the accuracy of their calculations. There is a consensus that the energy of the emitted photon may not be directly relevant to solving the uncertainty problem. Clarification on the correct application of the uncertainty principle is sought to resolve the issue.
Ezequiel
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Homework Statement



A Na atom is in an excited state for a mean time of 1.6 \times 10^{-8}s. Then it jumps to the ground state emitting a photon with 2.105 eV of energy. Find the energy uncertainty of that excited state.

Homework Equations





The Attempt at a Solution



I don't even know where to start. Any help would be appreciated!
 
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I just don't know how to use that to solve the problem. Could you be more specific?
 
Could it be \Delta E > \frac{\hbar}{2} \frac{1}{\Delta t} = 32.96 \times 10^{-28}J?
 
Ezequiel said:
Could it be \Delta E > \frac{\hbar}{2} \frac{1}{\Delta t} = 32.96 \times 10^{-28}J?

Doesn't seem to be correct. What you did basically? And the question mentions Na atom , so we cannot use bohr equations. Also I don't know why they gave you energy of de-excitation. There is no use of it , I guess... I think you used the correct equation but did not solve it correctly.
 
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