Entalphy of Formation: Why Use Water at Std Cond?

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Discussion Overview

The discussion revolves around the use of the enthalpy of formation of water at standard conditions for calculating the enthalpy of reactions, particularly addressing the state of water (liquid vs. gas) at standard temperature and pressure (STP).

Discussion Character

  • Technical explanation, Debate/contested

Main Points Raised

  • One participant questions the rationale for using the enthalpy of formation of water at standard conditions, noting that water is not in a gaseous state at 1 bar and 298K.
  • Another participant argues that a significant amount of water exists in gaseous form at room temperature and pressure, highlighting the importance of considering latent heat during condensation.
  • A different participant expresses confusion about the initial question, suggesting that the enthalpy of formation of water at STP assumes it is in liquid form.
  • One participant clarifies that there are two values for the heat of formation of water: one for liquid water and another for water vapor, indicating that the vapor value is relevant for calculations involving gaseous mixtures.

Areas of Agreement / Disagreement

Participants express differing views on the appropriateness of using the enthalpy of formation of water at standard conditions, indicating that multiple competing perspectives remain on this topic.

Contextual Notes

There are unresolved assumptions regarding the states of water and the conditions under which enthalpy values are applied, as well as the implications of latent heat in reaction calculations.

Est120
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why do we use the entalphy of formation of water at standard conditions to calculate the entalphy of a reaction even if water is not gas at 1bar and 298K
 
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A lot of water is in gaseous form at room temperature and pressure...
When gaseous water condenses to liquid, thermal energy is released. This is the latent heat of condensation. It is taken into account separately because formation enthalpy and condensation enthalpy are different things.
condensation enthalpy depends on the local saturation conditions, so if you want to know how much additional energy is released due to condensation, you have to compute how much water condenses. The difference in heat release between combustion with and without water condensation is the difference between the Higher Heating Value and the Lower Heating Value.
 
Est120 said:
why do we use the entalphy of formation of water at standard conditions to calculate the entalphy of a reaction even if water is not gas at 1bar and 298K

To be honest, I have no idea what you are asking about. Doesn't enthalpy of formation of water at STP assume water to be in a liquid form?
 
In the tables, there are two values for the heat of formation of water. One is for liquid water at 25 C and the standard pressure of 1 bar, and the other for the hypothetical state of water vapor at 25 C and 1 bar. The hypothetical state value is useful in many calculations where water vapor is part of a gaseous product mixture.
 

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