How Does Enthalpy Relate to Heat Capacity at Constant Composition?

AI Thread Summary
The discussion revolves around demonstrating the relationship between enthalpy and heat capacity at constant composition, specifically C_{Y,N} and its derivation from enthalpy H. The participants explore the equations relating heat capacity to entropy and internal energy, leading to a formulation involving pressure and volume changes. There is confusion regarding the selection of intensive variables and how they affect the calculations. The conversation highlights the need to apply the correct thermodynamic identities and derivatives to connect these concepts effectively. Ultimately, the thread emphasizes the complexity of deriving heat capacity from enthalpy while maintaining clarity on the definitions and relationships involved.
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Homework Statement


Demonstrate that C_{Y,N}=\left ( \frac{ \partial H}{\partial T } \right ) _{Y,N} where H is the enthalpy and Y is an intensive variable.


Homework Equations


(1) C_{Y,N}=\frac{T}{N} \left ( \frac{ \partial S}{\partial T } \right ) _{Y,N}
(2) T= \left ( \frac{ \partial U}{\partial S } \right ) _{X,N} where X is an extensive variable.

The Attempt at a Solution


Using (1) and (2) I reach that C_{Y,N}=T \left ( \frac{ \partial S}{\partial T } \right ) _{Y,N}+ P \left ( \frac{ \partial V}{\partial T } \right ) _{Y,N}. I don't know how to proceed further, I'm really stuck here.
 
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Which intensive variables are we talking about?
What do you get if you pick the first one that springs to mind?
 
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I like Serena said:
Which intensive variables are we talking about?
What do you get if you pick the first one that springs to mind?
Usually the pressure, but it is not specified.
C_{P,N}=\frac{T}{N} \left ( \frac{ \partial S}{\partial T } \right ) _{P,N}.
Where \left ( \frac{ \partial S}{\partial T } \right ) _{P,N}=\left ( \frac{ \partial U}{\partial T } \right ) _{P,N}\left ( \frac{ \partial S}{\partial U } \right ) _{P,N}=\frac{1}{T} \left ( \frac{ \partial U}{\partial T } \right ) _{P,N}.
Thus C_{P,N}= \frac{1}{N} \left ( \frac{\partial U }{\partial T } \right ) _{P,N }.
Now I use the relation U=H-PV to get \left ( \frac{ \partial U}{\partial T } \right ) _{P,N}=\left ( \frac{ \partial H}{\partial T } \right ) _{P,N} - \left [ \underbrace { \left ( \frac{ \partial P}{\partial T } \right ) _{P,N} V }_{=0} + P \left ( \frac{ \partial V}{\partial T } \right ) _{P,N} \right ].
Therefore I'm left with C_{P,N}=\frac{1}{N} \left [ \left ( \frac{ \partial H}{\partial T } \right ) _{P,N} - P \left ( \frac{ \partial V}{\partial T } \right ) _{P,N} \right ].
 
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Hmm, let's start with H=U+PV, or rather dH=TdS+VdP.

When I take the partial derivative with respect to T, and with P,N constant, I almost get what you're looking for (typo?).
 
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I like Serena said:
Hmm, let's start with H=U+PV, or rather dH=TdS-VdP.

When I take the partial derivative with respect to T, and with P,N constant, I almost get what you're looking for (typo?).
Hmm I don't think there's a typo.
Anyway you took the partial derivative of "dH"? I'm having some troubles to figure this out :)
 
dH=TdS+VdP
So:
$$\left({\partial H \over \partial T}\right)_{P,N}=\left({T\partial S + V\partial P \over \partial T}\right)_{P,N}$$

Factor out and replace with ##C_{P,N}## where applicable...
 
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