Enthelpy at the throat of the nozzle

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Discussion Overview

The discussion revolves around calculating the actual enthalpy at the throat of a nozzle using given parameters such as total enthalpy, inlet velocity, speed of sound, and outlet pressure. The focus is on applying thermodynamic principles and formulas to derive the enthalpy value.

Discussion Character

  • Technical explanation, Mathematical reasoning, Homework-related

Main Points Raised

  • One participant presents a scenario with total enthalpy, inlet velocity, speed of sound, and outlet pressure, seeking to calculate the enthalpy at the throat.
  • Another participant prompts for any attempts made by the original poster to solve the problem.
  • The original poster later describes a method involving a guessed value for enthalpy at the throat and using a solver in Excel to find the actual enthalpy by ensuring the difference between total enthalpy and throat enthalpy equals zero.
  • The original poster also mentions calculating pressure and temperature as functions of enthalpy and entropy.
  • A later reply acknowledges the original poster's success in finding the result and expresses understanding of the lack of initial responses.

Areas of Agreement / Disagreement

The discussion does not present any explicit areas of agreement or disagreement, as the original poster appears to have resolved their query independently.

Contextual Notes

Participants did not detail the assumptions made in their calculations or the specific conditions under which the formulas apply, leaving some aspects of the discussion open to interpretation.

Who May Find This Useful

Individuals interested in thermodynamics, nozzle flow calculations, and those seeking to understand enthalpy relationships in fluid dynamics may find this discussion relevant.

Naav_Gothalla
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Hi, This is my first post in this forum :woot:
I have a total enthalpy ht=3000 kj/kg with velocity at inlet v1=20 ms-1, Speed of sound a1=562.5 ms-1 and outlet pressure P2 = 1 bar
With the formula ht=h*+(a*2/2) how do i calculate actual value at throat h* ?

NOTE: (by trial and error)
  • I can take any guesses for enthalpy at throat and i start by considering h*=2800 Kj/kg
  • Total enthalpy and entropy remains constant at 3000 Kj/kg and Entropy with 6.5 Kj/K
  • ht-htinlet != 0 i.e Δ=0
 
Have you tried anything yourself yet?
 
boneh3ad said:
Have you tried anything yourself yet?
Yes , Sir I found the result.:partytime:
I guessed enthalpy at throat and i start by considering h*=2800 Kj/kg later on i find the speed of air(c*) = velocity of sound at throat(v*) for Mach 1. Furthermore, i calculate actual enthalpy at throat using the formula (h*=ht-c*2/2). I use a solver in excel such that Δh=(ht-h*) should be equal to zero there by finding the actual enthalpy at the throat. Next I calculate pressure and temperature which are a function of enthalpy and entropy.
 
Ah, good to hear that. Sorry no one answered your original post but it sounds like you didn't need it anyway. Carry on!
 

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