Entropy change in a reversible adiabatic process

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SUMMARY

In a reversible adiabatic process, the change in entropy (dS) is indeed zero due to the absence of heat transfer (dq = 0). The equation dS = dq/T applies, but since dq equals zero in an adiabatic process, it follows that dS must also equal zero. This conclusion is confirmed by the participant BiP, who validates the reasoning presented in the discussion.

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Bipolarity
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For a reversible process, I imagine it is correct to say that

dS = \frac{dq}{T} where all quantities refer to system quantities (not the surrounding).

However, for an adiabatic process, dq = 0.

Thus, should it be the case that for an adiabatic reversible process,

dS = \frac{dq}{T} = \frac{0}{T} = 0

Please correct me if I am wrong, and point out the flaws in my reasoning.

BiP
 
Science news on Phys.org
Entirely correct.
 

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