MHB Equality of Angles: 3 Equal Angles in a Picture

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Can you explain why the 3 angles in the picture are the same.
 

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There is a theorem saying that two angles whose sides are mutually perpendicular are equal.
 
Drain Brain said:
Can you explain why the 3 angles in the picture are the same.
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The sum of the angles of a triangle is equal to $180$.

The angles $\hat{F_1}$ and $\hat{F_2}$ are a pair of vertical angles, so they are equal, $\hat{F_1}=\hat{F_2}$

At the triangle $BFD$, the sum of the angles is:
$$\theta_2+\hat{F_2}+90 ^{\circ}=180^{\circ} \Rightarrow \theta_2+\hat{F_2}=90^{\circ} \ \ \ (1)$$

At the triangle $CEF$, the sum of the angles is:
$$\theta_3+\hat{F_1}+90^{\circ}=180 \Rightarrow \theta_3+\hat{F_1}=90^{\circ} \ \ \ (2)$$

$$\xrightarrow[(1)]{(2)} \theta_2+\hat{F_2}=\theta_3+\hat{F_1} \Rightarrow \theta_2=\theta_3$$

Then we do the same for the triangles $OFC$ and $BDF$ and we conclude that $\theta_1=\theta_2=\theta_3$
 

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Evgeny.Makarov said:
There is a theorem saying that two angles whose sides are mutually perpendicular are equal.

what do you mean? Can you show me a picture of mutually perpendicular angles? please bear with me. :) thanks!
 
I mean the following situation.

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If you consider angles composed of two rays (semi-lines) rather than lines infinite in both directions, then the angles may add up to $180^\circ$. But if you have two pairs of lines: $l_1,l_2$ and $l_1',l_2'$ such that $l_1\perp l_1'$ and $l_2\perp l_2'$ and if you consider the smaller angles formed by these lines, then these angles are equal.

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This property is especially useful in physics for solving problems with inclined plane.
 

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