What is the equation of the angle bisector formed by two intersecting lines?

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The equation of the angle bisector formed by two intersecting lines, represented as r = Ax + By + C = 0 and r = Dx + Ey + F = 0, is given by |Ax + By + C|/√(A²+B²) = |Dx + Ey + F|/√(D²+E²). This formulation arises because the angle bisector is the locus of points that are equidistant from both lines. The distances from any point on the bisector to each line are equal, which justifies the equation. Thus, the angle bisector effectively represents all points maintaining equal distance to the two intersecting lines. Understanding this relationship clarifies the geometric significance of the angle bisector in coordinate geometry.
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I've seen that if you have two lines: r = Ax + By + C = 0 and r = Dx + Ey + F = 0, you can say the equation of the line that is the angle bisector of r and s is given by: \frac{|Ax + By + C|}{\sqrt{A^2+B^2}}=\frac{|Dx + Ey + F|}{\sqrt{D^2+E^2}}.
Why is that?

I would think to equate the distances from the angle bisector to each line. Is that what is happening here?
 
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V0ODO0CH1LD said:
I would think to equate the distances from the angle bisector to each line. Is that what is happening here?
Yes.
Angular bisector of an angle made by two lines is the locus of all points which are equidistant from both the lines. So that the equation of the bisector is given by equating the distances...
 
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