Equation of curves (intersection)

madachi
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Homework Statement



Let S be the solid region bounded by the paraboloid z = x^2 + y^2 - 4 for z \le 0, 0 \le x \le \sqrt{4 - y^2} and 0 \le y \le 2. Find the Cartesian equations of the curves if the surface S intersects the xy,xz, and yz planes.


The Attempt at a Solution



Is the question asking us to find the equation of the intersection of z = x^2 + y^2 - 4 and z=z, z=x, and z=y respectively?

As I am confused with this question and not really sure how to start, so there is no attempt yet but I had some thought about this question. Could you tell me some hints to start the problem?

Thanks!
 
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i would take the xy plane to be where z = 0
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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