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find the equation of the normal line to the curve y = -3x^2 at the point (-1,-3).
you have to use derivatives.
i am not asking for the equation of the tangent line i know that is 6x + 3. please show all the steps.
the answer is y = -1/6x - 19/6
you have to use derivatives.
i am not asking for the equation of the tangent line i know that is 6x + 3. please show all the steps.
the answer is y = -1/6x - 19/6