Equations for Calculating Momentum in Pole Vaulting Collisions

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The discussion centers on whether the collision in pole vaulting is elastic or inelastic, with the consensus leaning towards it being akin to swinging on a rope rather than a traditional collision. Participants suggest using conservation of energy principles, including spring energy from the bending pole, to analyze the situation. The equations proposed for calculating momentum are debated, with a focus on the correct application of momentum conservation. Ultimately, the conversation emphasizes the importance of energy conservation over momentum equations in this context. Understanding these dynamics is crucial for accurately assessing the pole vaulter's momentum upon release.
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Is the collison of the olympic sport polevolting elastic or inelastic? The pole collides with the Earth and stays at that point until the polevolter let's go. So wouldn't you use the momentum equations to see how much momentum the polevolter has once he let's go of the pole?

Which one of the following equations would I use to find the momentum of the polevolter once he has let go of his pole? mv1+mv2=mv1+mv2 or mv1+mv2=(m+m)v

Thank you.

Stephen
 
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StephenDoty said:
So wouldn't you use the momentum equations to see how much momentum the polevolter has once he let's go of the pole?

Hi Stephen! :smile:

It's not a collison … it's exactly like swinging on a rope (but upside down :wink: ).

So you'd just use conservation of energy (including some "spring" energy for the bending of the pole). :smile:
 
so you would have 1/2mv1^2 + 1/2kx^2 +mgh0= 1/2mv2^2 + 1/2kx^2 +mgh1?
 
Yup! :biggrin:
 
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