Equivalence mapping from integers to rationals

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SUMMARY

The discussion centers on the equivalence mapping from integers to rationals defined by the operations * and =, where a*b indicates that a - b is an integer and a = b indicates that a - b is a rational number. The mapping P from the equivalence classes of * to those of = is confirmed to be onto and well-defined. The equivalence classes of * are represented as r + Z, while those of = are represented as s + Q, where r and s are real numbers. A clear definition of the mapping is essential for proving its properties.

PREREQUISITES
  • Understanding of equivalence relations in mathematics
  • Familiarity with real numbers, integers, and rational numbers
  • Knowledge of mapping functions and their properties
  • Basic proof techniques in abstract algebra
NEXT STEPS
  • Define the mapping P explicitly to facilitate proof of its properties
  • Explore the concept of equivalence classes in more depth
  • Study the implications of mapping between different number sets
  • Investigate the properties of well-defined functions in mathematical contexts
USEFUL FOR

Students and educators in mathematics, particularly those studying abstract algebra and equivalence relations, as well as anyone interested in the properties of mappings between different number sets.

PsychonautQQ
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Homework Statement


Let * and = be defined by a*b means a - b is an element of the integers and a = b means that a - b is an element of the rationals. Suppose there is a mapping P: (* equivalence classes over the real numbers) --> (= equivalence classes over the real numbers). show that this mapping is onto and well defined.

Homework Equations


None.

The Attempt at a Solution


I'm confused, wouldn't this mapping NOT be onto? I mean, if you take all the equivalence classes defined by * it couldn't cover all the equivalence classes covered by =, since = deals with rationals and * integers. Is this a misprint in the book or am I mistaken?
 
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PsychonautQQ said:

Homework Statement


Let * and = be defined by a*b means a - b is an element of the integers and a = b means that a - b is an element of the rationals. Suppose there is a mapping P: (* equivalence classes over the real numbers) --> (= equivalence classes over the real numbers). show that this mapping is onto and well defined.

Homework Equations


None.

The Attempt at a Solution


I'm confused, wouldn't this mapping NOT be onto? I mean, if you take all the equivalence classes defined by * it couldn't cover all the equivalence classes covered by =, since = deals with rationals and * integers. Is this a misprint in the book or am I mistaken?

Mistaken. If Z is the integers and Q is the rationals, then an equivalence class of * is a set of the form r+Z where r is a real number. An equivalence class of = is a set of the form s+Q where s is real. Can't you think of a sort of obvious way to map one onto the other? Then try and prove your map is well defined and onto. You can't really prove a map is anything until you define it.
 
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Oh. right, Thanks dood u da best
 

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