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Equivalence of Boltzmann and Clausius entropy

  1. Dec 4, 2008 #1
    I can't figure out how to show that the Clausius entropy

    [tex] \Delta S= \int_{T_1}^{T_2} \frac{dQ}{T}[/tex]

    is equivalent to the Boltzmann entropy

    [tex] S=kln \Omega [/tex]

    at thermal equilibrium.

    Does anyone know how to do this?
  2. jcsd
  3. Dec 7, 2008 #2
    Might want to see how it works for monoatomic ideal gas first, then look for a generalization.
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