Bobhawke
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I can't figure out how to show that the Clausius entropy
[tex]\Delta S= \int_{T_1}^{T_2} \frac{dQ}{T}[/tex]
is equivalent to the Boltzmann entropy
[tex]S=kln \Omega[/tex]
at thermal equilibrium.
Does anyone know how to do this?
[tex]\Delta S= \int_{T_1}^{T_2} \frac{dQ}{T}[/tex]
is equivalent to the Boltzmann entropy
[tex]S=kln \Omega[/tex]
at thermal equilibrium.
Does anyone know how to do this?