Meaning of thermodynamic probability

Click For Summary

Discussion Overview

The discussion revolves around the concept of thermodynamic probability as it relates to Boltzmann's entropy relation, specifically the interpretation of the term ##Ω## in the equation ##S = k_B\ln Ω##. Participants explore the meaning of ##Ω## in the context of statistical mechanics and its implications for understanding entropy.

Discussion Character

  • Conceptual clarification
  • Technical explanation

Main Points Raised

  • One participant seeks clarification on the meaning of ##Ω##, questioning what it signifies in relation to thermodynamic probability and entropy.
  • Another participant states that ##Ω## represents the number of microstates corresponding to a relevant macrostate.
  • A subsequent reply confirms that ##S## is indeed the entropy of that macrostate.
  • A reference to Wikipedia is made, indicating that entropy is related to the number of microscopic configurations consistent with macroscopic quantities.
  • A participant expresses confusion regarding the term "thermodynamic probability," noting that it suggests properties typical of probability, such as summation equaling one.

Areas of Agreement / Disagreement

Participants generally agree on the interpretation of ##Ω## as the number of microstates associated with a macrostate and its relation to entropy. However, there is some confusion regarding the terminology of "thermodynamic probability" and its implications.

Contextual Notes

There are unresolved questions about the properties of ##Ω## as a probability and how it relates to the concept of summation in probability theory.

Saptarshi Sarkar
Messages
98
Reaction score
13
I was studying statistical mechanics when I came to know about the Boltzmann's entropy relation, ##S = k_B\ln Ω##.

The book mentions ##Ω## as the 'thermodynamic probability'. But, even after reading, I can't understand what it means. I know that in a set of ##Ω_0## different accessible states, an isolated system has a probability ##P = \frac 1 {Ω_0}## of being in anyone of the state and that at equilibrium when entropy is maximum, the probability of the system being in various accessible states do not vary with time. Also, when two interacting systems are in equilibrium, the no of states available to the combines system is maximum.

In the Boltzmann's entropy relation, ##S = k_B\ln Ω##, what does the ##Ω## signify? If it is a probability what is it the probability of and for which system are we getting the Entropy?
 
Science news on Phys.org
##\Omega## is the number of microstates corresponding to the relevant macrostate.
 
  • Informative
Likes   Reactions: Saptarshi Sarkar
Orodruin said:
##\Omega## is the number of microstates corresponding to the relevant macrostate.

So, S is the entropy of that macrostate?
 
Saptarshi Sarkar said:
So, S is the entropy of that macrostate?
Yes. This is in the first paragraph on Wikipedia’s page on entropy:
In statistical mechanics, entropy is an extensive property of a thermodynamic system. It is closely related to the number Ω of microscopic configurations (known as microstates) that are consistent with the macroscopic quantities that characterize the system (such as its volume, pressure and temperature). Entropy expresses the number Ωof different configurations that a system defined by macroscopic variables could assume.[1]
 
  • Haha
Likes   Reactions: Saptarshi Sarkar
Orodruin said:
Yes. This is in the first paragraph on Wikipedia’s page on entropy:

I guess checking Wikipedia will be the first thing I do from now on. I got confused as it was called thermodynamic probability and thought that it should have the properties of probability (summation = 1).

Thanks for the help!
 

Similar threads

  • · Replies 18 ·
Replies
18
Views
6K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
4
Views
1K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 8 ·
Replies
8
Views
7K