Estimating Bandwidth of Phase Modulated Signal Using Taylor Series

AI Thread Summary
The discussion focuses on estimating the bandwidth of a phase-modulated (PM) signal using Taylor series expansion. The signal is represented as s(t) = Acos(wt + x(t)), where x(t) is the information-bearing signal constrained by |x(t)| < y. Participants discuss deriving the Taylor series expansion and substituting the maximum value of x(t) to simplify the expression. The conversation highlights the importance of considering the second-order terms in the expansion to estimate the bandwidth. Ultimately, the discussion emphasizes the need to analyze the coefficients of the resulting power series to draw conclusions about the bandwidth of the PM signal.
ace1719
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Homework Statement


Consider the PM (phase modulated) signal, s(t) = Acos(wt+x(t)) where x(t) is the information bearing signal. Assume that |x(t)|< y, which is not necessarily small. Using Taylor's series expansion, derive an estimate for the bandwidth of the PM signal s(t).


Homework Equations





The Attempt at a Solution


I was able to get the Taylor series expansion of s(t). I'm guessing the relevant part of the expansion is (wt+x(t))^2k. At this point I would guess that you'd want to substitute the maximum value of x(t) in - which is y - to get, (wt+y)^2k. If you couldn't tell, this required a lot of guess work, but I'm lost as to what to do at this point.

I'll thank you for your help in advance.
 
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I am not sure where your k came from but the Taylor series expansion up to fourth order is
$$
1 - \frac{(wt + x(t))^2}{2} + \frac{(wt + x(t))^4}{24} - \cdots
$$
Is ##\lvert x(t)\rvert## absolute value or the modulus?
 
k is the index for the summation. I guess I should have explained that. |x(t)|, I presume is absolute.
 
ace1719 said:
k is the index for the summation. I guess I should have explained that. |x(t)|, I presume is absolute.

The we could say an estimate of ##s(t)## is then
$$
s(t) \approx A\Bigg(1 - \frac{(wt + x(t))^2}{2}\Bigg) < A - A\frac{(wt + y)^2}{2}
$$
where I took only up to second order terms. You wouldn't have a k in your solution.
 
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What can we infer about the bandwidth of that?
 
cos(wt + x(t)) = cos(x) cos(wt) - sin(x) sin (wt).
Expand cos(x) and sin(x) in power series. You know |x| is limited to y and I would think y = pi is the biggest it can get. So keep terms in n until xn/n! << 1. These are the coefficients of cos(wt) and sin(wt). When you multiply cos (nwT) by cos(wt) you get what? keep the sum term.

That should get you where you want to go.
 
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