Estimating Vc of transistor (darlington)

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To estimate the collector voltage (VC) of a transistor with input voltages of +1V, +2V, and +3V, it is essential to consider the transistor's configuration and the gain factor (IC/IB = 1000). The discussion clarifies that a Darlington connection was mistakenly referenced, and the correct approach involves calculating the voltage across a 200 K resistor after accounting for a 0.6V drop across the base-emitter junction. The base current can then be determined, which is multiplied by the gain to find the collector current. Finally, the voltage across the collector resistor needs to be evaluated to determine if the transistor is saturated, allowing for accurate VC estimation. Understanding these steps is crucial for solving the problem effectively.
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Homework Statement



Estimate the collector voltage VC when vin is +1, +2 and +3V. (assume IC/IB = 1000)

Homework Equations



IC/IB = 1000

The Attempt at a Solution



I know that a transistor becomes saturated when VCE and RCE are reduced to 0 and when the maximum IB flows, but in this instance, how can you tell if the darlington is partly-on or fully on (for the +2 and 3V)?
 

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TsAmE said:

Homework Statement



Estimate the collector voltage VC when vin is +1, +2 and +3V. (assume IC/IB = 1000)

Homework Equations



IC/IB = 1000

The Attempt at a Solution



I know that a transistor becomes saturated when VCE and RCE are reduced to 0 and when the maximum IB flows, but in this instance, how can you tell if the darlington is partly-on or fully on (for the +2 and 3V)?

That's not a Darlington connection. But the gain you quote (1000) would fit with a Darlington connection.

Is the figure misdrawn? It's important to show the full (2 x NPN) Darlington configuration if you want to get the voltage drops correct.
 
Sorry I ment for an NPN transistor, there was a similar question with a darlington I did that's why I wrote darlington by mistake.
 
With one base-emitter junction, assume 0.6 volts across it before current will flow.

So, work out the voltage across the 200 K resistor for the various input voltages (ie subtract 0.6 volts from each input).

Then work out the current in the 200 K. This is the base current.

Then multiply this by 1000 to get the collector current.

Then work out the voltage across the collector resistor when that current flows in it. If this is more than the supply voltage, the transistor is saturated and this current can't really flow.

Subtract this from the supply voltage to get the voltage across the transistor.
 
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Oh I see, thanks a lot :)
 

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