Estimation example from Giancoli

AI Thread Summary
The discussion focuses on understanding a volume estimation example from the Giancoli physics textbook, specifically how to calculate the volume of a lake using rough measurements. The user is confused about the calculation leading to the result of 8×10^6 m³, particularly in squaring the radius and applying the rules of multiplication with exponents. Clarifications provided emphasize the importance of squaring the radius correctly and rounding the final result to one significant figure. The correct process involves calculating the squared radius, multiplying by the average depth, and then applying the approximation for π. Overall, the explanation resolves the user's confusion and reinforces key mathematical principles.
EvD
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Hello, I´m a bit math-challenged and just started to brush up on both physics and mathematics simultaneously but I'm still at absolute beginner status and I don't want to go on in the book as long as I can't even figure out such a simple example. I'm using the Giancoli textbook on physics for self-study but can't quite follow the simplest of examples in the first chapter. Since the problem lies in the mathematical part of my understanding and not the conceptually physical part I thought I'd post it here. Just wanted to check if I'm doing something wrong or whether there's a typo in the example because unfortunately there doesn't seem to be a list of errata for the book. Here it is:

1. Homework Statement

The example is about estimating the volume of a lake by using some rough measures and rounded-off numbers to get at the approximate order-of-magnitude.
So it says:

V=hπr2 ≈(10meters) × (3) ×(5×102meters)2≈8×106m3 ≈ 107 m3

where π has been rounded to 3, the average depth of the lake is 10m and the estimated radius of the surface is given by 5×102 (500 m).
I can't seem to follow how he arrives at 8 ×106.

Homework Equations


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The Attempt at a Solution


In my mind it would come to 3×(5×105) and then maybe 1.5×101 ×105 and then 1.5 ×106. This is of course different from the given 8×106.

I figure I'm probably making a mistake here in the rules of multiplication of exponents and bracketing out but I can't figure out what it is. Any help would be much appreciated. Sorry for the absolute rookie level of mathematical (in)competence.
 
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EvD said:
Hello, I´m a bit math-challenged and just started to brush up on both physics and mathematics simultaneously but I'm still at absolute beginner status and I don't want to go on in the book as long as I can't even figure out such a simple example. I'm using the Giancoli textbook on physics for self-study but can't quite follow the simplest of examples in the first chapter. Since the problem lies in the mathematical part of my understanding and not the conceptually physical part I thought I'd post it here. Just wanted to check if I'm doing something wrong or whether there's a typo in the example because unfortunately there doesn't seem to be a list of errata for the book. Here it is:

1. Homework Statement

The example is about estimating the volume of a lake by using some rough measures and rounded-off numbers to get at the approximate order-of-magnitude.
So it says:

V=hπr2 ≈(10meters) × (3) ×(5×102meters)2≈8×106m3 ≈ 107 m3

where π has been rounded to 3, the average depth of the lake is 10m and the estimated radius of the surface is given by 5×102 (500 m).
I can't seem to follow how he arrives at 8 ×106.

Homework Equations


-

The Attempt at a Solution


In my mind it would come to 3×(5×105) and then maybe 1.5×101 ×105 and then 1.5 ×106. This is of course different from the given 8×106.

I figure I'm probably making a mistake here in the rules of multiplication of exponents and bracketing out but I can't figure out what it is. Any help would be much appreciated. Sorry for the absolute rookie level of mathematical (in)competence.

Don't forget to square the radius: (5×102)2 = 500 × 500 = 250,000

Multiply by the average depth: 250,000 × 10 = 2,500,000

Multiply by π (approx.): 2,500,000 × 3 = 7,500,000

Round final result to 1 significant figure: 7,500,000 ≈ 8,000,000 or 8×106 m3

Personally, I find writing some numbers in scientific notation tedious and confusing (for example, 5×102 for 500).

When you do square numbers written in scientific notation, remember to square the first part but double the exponent on the 10:

(5×102)2 = 25×104 = 2.5×105 = 250,000
 
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SteamKing said:
Don't forget to square the radius: (5×102)2 = 500 × 500 = 250,000

Multiply by the average depth: 250,000 × 10 = 2,500,000

Multiply by π (approx.): 2,500,000 × 3 = 7,500,000

Round final result to 1 significant figure: 7,500,000 ≈ 8,000,000 or 8×106 m3

Personally, I find writing some numbers in scientific notation tedious and confusing (for example, 5×102 for 500).

When you do square numbers written in scientific notation, remember to square the first part but double the exponent on the 10:

(5×102)2 = 25×104 = 2.5×105 = 250,000

Ah right of course. Thanks a million! That made a lot of sense and really helped me!
 
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