Estimation Theory: Get Help Understanding Binomial Proportion

  • Thread starter Thread starter mike1111
  • Start date Start date
  • Tags Tags
    Estimation Theory
mike1111
Messages
8
Reaction score
0
I got a question on estimation theory. Can anyone explain it to me or give me a link with some tut and solutions so I can get a better understanding.

I got a maths question which i have asked for help but no one has replied yet. Since it was a statistical question I should have posted it here.

The question can be found here:
https://www.physicsforums.com/showthread.php?t=401521

I'm stuck on part (b)
The two issue I think I have with the question are that I don't understand the term "binomial proportion" and estimation theory in general. Can and one explain this to me?
 
Physics news on Phys.org
Is the "binomial proportion" just the probability the event is successful?
i.e. for 2 coin toss with 50/ 50 chance of either H or T, the binomial proportion for 2 heads is 1/4?

Is my understanding correct... or is it something else?
 
A binomial probability is the probability that a random sample of size n will have an outcome of x. The equation is

P(x) = n!/(k!-(n-k)!) * pk * qn-k

where k is number of outcomes you want,
p is probability of an outcome,
q is probability of an outcome not happening.

For example, suppose that there are 999 voters in the US. 599 voters were in favor for a certain candidate. If I randomly select 110 voters out of the population, the probability that 56 voters will be in favor of the candidate is

110!/(56!-(110-56)!) * .599599656 * .400400454 = 2.2345492668874894732687678194543e+103 * .599599656 *q54 =
3.632743322467059575061399533725e-13 * q54

gives me a probability of 1.2443365480583675485269518116737 e-34 :confused:
 
Last edited:
Hi all, I've been a roulette player for more than 10 years (although I took time off here and there) and it's only now that I'm trying to understand the physics of the game. Basically my strategy in roulette is to divide the wheel roughly into two halves (let's call them A and B). My theory is that in roulette there will invariably be variance. In other words, if A comes up 5 times in a row, B will be due to come up soon. However I have been proven wrong many times, and I have seen some...
Namaste & G'day Postulate: A strongly-knit team wins on average over a less knit one Fundamentals: - Two teams face off with 4 players each - A polo team consists of players that each have assigned to them a measure of their ability (called a "Handicap" - 10 is highest, -2 lowest) I attempted to measure close-knitness of a team in terms of standard deviation (SD) of handicaps of the players. Failure: It turns out that, more often than, a team with a higher SD wins. In my language, that...
Back
Top