Euler's Formula Contradiction?

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Discussion Overview

The discussion revolves around the application of Euler's formula, particularly in the context of circuit analysis. Participants explore the implications of taking the natural logarithm of both sides of the equation e^{2πi}=1, leading to a perceived contradiction.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant notes a contradiction arising from applying the natural logarithm to e^{2πi}=1, leading to the equation 2πi=0.
  • Another participant points out that the issue stems from using the real natural logarithm instead of the complex logarithm.
  • A later reply reiterates the need for the complex logarithm to resolve the contradiction.
  • Another participant introduces the general equation e^{±2niπ}=1, emphasizing the periodic nature of the function e^{ix} and its similarity to trigonometric functions.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the initial contradiction, but there is agreement on the necessity of using the complex logarithm for this context. The discussion includes competing views on the implications of periodicity in the exponential function.

Contextual Notes

The discussion highlights the limitations of applying the real logarithm to complex exponentials and the need for clarity regarding the definitions of logarithmic functions in different contexts.

TheDemx27
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I've been using euler's formula now more than I have in the past, (using it for circuit analysis stuff), and so its been floating around in my head a bit more.

Say you have e^{2πi}=1 and you take the natural log of both sides.

\log_e( e^{2πi})=\log_e(1)
2πi=0
uhhhhh... :confused:
 
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The problem is that you are using the real natural logarithm, which is the inverse of the real exponential function e^x. You need to use the complex logarithm.
 
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axmls said:
The problem is that you are using the real natural logarithm, which is the inverse of the real exponential function e^x. You need to use the complex logarithm.
Ah, thankyou.
 
The general equation is ##e^{\pm 2ni\pi}=1##
The function ##e^{ix}## has periods of ##2\pi##, just as the trigonometric functions have periods of ##2\pi##
[i.e. although ##sin(2\pi)=sin(0),\ 2\pi\neq0##]
 
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