The discussion revolves around evaluating the integral of the function (cos x) / (7 + sin x) between the limits of pi/2 and pi/6. Participants are exploring different approaches to the integration process and discussing algebraic manipulations involved in the problem.
The discussion is ongoing, with various approaches being considered. Some participants have expressed confidence in their methods, while others have raised concerns about the correctness of earlier steps. There is no explicit consensus on the best approach yet, but multiple strategies are being explored.
Participants note varying levels of mathematical experience, with some indicating recent returns to calculus after a break. This context may influence the understanding and approaches to the problem.
If you are taking calculus, your algebra should be better than that! cos(x)/(7+ sin(x)) is NOT (1/7) cos(x)/sin(x).intenzxboi said:Homework Statement
between pi/2 and pi/6[tex]\int[/tex] (cos x) / (7 + sin x)
move 1/7 to the out side
1/7 [tex]\int[/tex] cos x / sin x
Mark got in just ahead of me but I think my suggestion for integrating it is easier!u= sin x
du= cos x
so i get
1/7 ln sinx + C
then plug pi/2 minus pi/6?
Yes, I agree. It just goes to show that "haste makes waste."HallsofIvy said:Instead use the substitution u= 7+ sin x.
Mark got in just ahead of me but I think my suggestion for integrating it is easier!