Evaluate using Integration by parts

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SUMMARY

The integral from 1 to 5 of xg'(x)dx can be evaluated using integration by parts, yielding a final answer of 46. The process involves calculating xg(x) from 1 to 5, which results in 40 - 3 = 37, and then incorporating the known integral of g(x)dx from 1 to 5, which is -9. The correct application of the integration by parts formula, ∫_a^b u dv = [uv]_a^b - ∫_a^b v du, is crucial for arriving at the correct solution.

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  • Understanding of integration by parts
  • Familiarity with definite integrals
  • Knowledge of function evaluation at specific points
  • Basic calculus concepts
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Students studying calculus, particularly those focusing on integration techniques, as well as educators looking for examples of integration by parts applications.

waealu
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Homework Statement



If g(1)=3, g(5)=8 and the integral from 1 to 5 of g(x)dx=-9. Then, evaluate the integral from 1 to 5 of xg'(x)dx.

2. Homework Equations and attempt at solution

I used integration by parts to get =xg(x)-(integral of)g(x)dx from 1 to 5. Then substituting in, I get ((5)(8)+9)-((1)(3)+9)=37

Apparently that answer is incorrect. What am I missing? Thanks.
 
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waealu said:

Homework Statement



If g(1)=3, g(5)=8 and the integral from 1 to 5 of g(x)dx=-9. Then, evaluate the integral from 1 to 5 of xg'(x)dx.

2. Homework Equations and attempt at solution

I used integration by parts to get =xg(x)-(integral of)g(x)dx from 1 to 5. Then substituting in, I get ((5)(8)+9)-((1)(3)+9)=37

Apparently that answer is incorrect. What am I missing? Thanks.

You didn't think of the integral in the right way. You are already provided the answer for the complete integral of g(x)dx. You don't need to apply it twice.

you should get xg(x) from 1 to 5 giving you 40-3=37. Then the integral will give you --9=+9

Final answer is 37+9=46

Note: [tex]\int_a^b u\; dv=[uv]_a^b-\int_a^b v\; du[/tex]
 

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