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Evaluating an Integral in Polar Coordinates

  1. Nov 2, 2013 #1
    1. The problem statement, all variables and given/known data
    Evalutate the double integral sin(x^2+y^2)dA between the region 1≥x^2+y^2≥49



    3. The attempt at a solution
    so r^2 = x^2 + y^2
    dA = rdrdθ

    so I can turn this into
    double integral sin(r^2)rdrdθ
    where the inner integral integrated with respect to dr goes from 1 to 7?
    and then what are the parameters for integrating with respect to θ? 0 to 2pi?
    Does this look correct?
     
  2. jcsd
  3. Nov 2, 2013 #2
    To clarify your question: it gives no boundary conditions for your [itex]\theta[/itex] axis, so you are integrating over a disk of radius 7 (starting at 1). So yes your integral seems correct.
     
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