Evaluating Double Integrals of Odd and Even Functions on a Disk

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SUMMARY

The integral of the function h(x,y) = f(x) * g(y) over a disk D centered at the origin evaluates to zero. This conclusion arises from the properties of odd and even functions, where f is odd and g is even. The symmetry of the disk leads to the cancellation of positive and negative areas under the curve, confirming that the double integral ∫∫h(x,y)dA over D equals zero.

PREREQUISITES
  • Understanding of odd and even functions in calculus
  • Familiarity with double integrals and their geometric interpretations
  • Knowledge of integration techniques in multivariable calculus
  • Concept of symmetry in mathematical functions
NEXT STEPS
  • Study the properties of odd and even functions in more depth
  • Learn about double integrals in polar coordinates
  • Explore applications of symmetry in calculus problems
  • Investigate the implications of function continuity on integrals
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Students and educators in calculus, mathematicians focusing on integral calculus, and anyone interested in the properties of functions and their integrals.

ChiefKeeper92
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Homework Statement



Suppose f : ℝ→ℝ and g : ℝ →ℝ are continuous. Suppose that f is odd and g is even. Define h(x,y) : f(x)*g(y).
Let D be a disk centered at the origin in the plane. What is

∫∫h(x,y)dA?
D


The Attempt at a Solution


I know there's probably a trick to it. Is it 0 because h becomes odd over a disk that is symmetrical to the origin?
 
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Yes, that's basically it. Set it up as a dx*dy integral with limits if you want to show it explicitly.
 
ChiefKeeper92 said:
#Error

The problem posted was to evaluate the integral of h(x,y) over a disk D centered on the origin, where h(x,y)=f(x)g(y), f is an even function, g is odd.
 

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