Evaluating Functions in MATLAB with x,y Range 1-1000

[jaejoon89]

Using MATLAB, how do you evaluate a function at integer values, say 1 to 1000, of x and y? For simplicity, let's say the function is z = x + y.

 

[mikeph]

Hello

Try a loop within a loop to go through all x values then all y values?

z = zeros(1000);
for x= 1:1000
    for y = 1:1000
        z(x,y) = x + y;
    end
end

 

[matonski]

[x y] = meshgrid(1:1000);
z = x + y;

 

[mfarooq52003]

Hi
Can anyone help how to write the matrix
A=[ 2 1 0 0 0
0 2 1 0 0
1 0 2 1 0
0 1 0 2 1
0 0 1 0 2]
I need A with the above pattern of any dimension n and also a vector of the form
v=[3 3 4 4 4 4 ...4 3 3]^T where v can be of any dimension. I'll be grateful for your help.

 

[blue_raver22]

To evaluate a function at integer values of x and y in MATLAB, you can use the "meshgrid" function to create a grid of x and y values ranging from 1 to 1000. Then, you can use the "eval" function to evaluate the function at each point on the grid and store the results in a matrix. In this case, the code would look something like this:

[x,y] = meshgrid(1:1000, 1:1000); % create a grid of x and y values
z = eval('x + y'); % evaluate the function at each point on the grid and store the results in a matrix
plot3(x,y,z); % plot the results in 3D to visualize the function's surface