Evaluating Infinite Series: (2^n)/(n!) from n=0 to infinity

lvuittongirl22
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How do I evaluate the infinite series (2^n)/(n!) from n=0 to infinity?
(I don't know how you put the little E symbol and all that in so I had to write it out.)

I already found that it converges to 0 using the ratio test, but I don't know quite how to evaluate it.

Any help would be mondo appreciated! Thank you!
 
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Have you dealt with Taylor's series? In particular, do you know the Taylor's series for ex?
 
We went over them, but I'm not sure how to use them...
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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