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Evaluating Integral with a natural log

  1. Sep 1, 2008 #1
    I hit the submit instead of the preview. please wait
    1. The problem statement, all variables and given/known data
    [tex]\int9s9^s ds[/tex]


    2. Relevant equations
    ∫udv=uv-∫9^sds-∫vdu


    3. The attempt at a solution
    u=9s
    du=9ds

    dv=9^s ds
    v=∫9^sds
    =∫3^(2s) ds
    =3^(2s)/[2ln(3)]
    this is as far as i have gotten. Am i correct so far?
     
    Last edited: Sep 1, 2008
  2. jcsd
  3. Sep 2, 2008 #2

    HallsofIvy

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    Staff Emeritus
    Science Advisor

    Yes, that is correct. You didn't really need to reduce to 3, that is exactly the same as
    [tex]\int 9^s ds= 9^s/ln(9)[/tex]
     
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