Evaluating Motor Specifications for a Conveyor

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Discussion Overview

The discussion revolves around evaluating motor specifications for a chain and sprocket conveyor system. Participants explore the necessary parameters and calculations needed to determine if the motor is adequate for the intended operation, which includes moving panels at a specified speed of approximately 7 meters per minute. The conversation touches on mechanical principles, power requirements, and motor characteristics.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant expresses uncertainty about how to start evaluating the motor specifications and seeks foundational knowledge about mechanics.
  • Another participant questions the purpose of the machine and emphasizes the need to know the resistance to motion, which depends on the weight of the panel.
  • It is noted that the motor output is 1000Nm with a 137:1 gear reduction, prompting a discussion about the final output torque required.
  • Some participants suggest calculating the force of resistance using F=ma, while others propose determining the motor size constant (KM) to assess motor requirements.
  • Participants discuss the importance of estimating power requirements to overcome friction and accelerate the panels, along with considerations for the conveyor's level path.
  • There are suggestions to analyze gear ratios and motor specifications, including Kv (max unloaded rpm per volt) and Kt (torque per amp), to ensure the motor can operate efficiently.
  • A later reply mentions the significance of finding an optimal gear ratio to maintain motor efficiency, considering resistive and iron losses.

Areas of Agreement / Disagreement

Participants generally agree on the need to understand the power requirements and motor specifications, but multiple competing views remain regarding the calculations and parameters necessary for evaluation. The discussion is ongoing and unresolved.

Contextual Notes

Participants highlight the importance of knowing the weight of the panel and the resistance to motion, which are not yet defined. There is also uncertainty about how to apply the motor constant and other specifications to the problem.

Who May Find This Useful

Individuals interested in mechanical engineering, motor specifications, conveyor design, and those seeking to understand the principles of motion resistance and power calculations in machinery may find this discussion beneficial.

  • #31
Devin-M said:
Are you sure this part’s diameter is 70mm (2.76in) and not 70cm (27.5in or 2.2ft)?
View attachment 344907
Sorry I forgot to mention that I got the 70 mm from the shaft coming out the motor, the one you have shown is the sprocket that moves the conveyor belt, I did this because @jrmichler mentioned to measure the rpm coming OUT the motor
 
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  • #32
jrmichler said:
That's the same that I get assuming 10 meters per minute and a 70 mm diameter conveyor drive roll. The next step is:

Another way to get the drive torque is to place the maximum load on the conveyor, wrap a long string around the drive roll, and pull the string using a spring scale. From the force to move the conveyor belt, and the radius of the drive roll (35 mm), you calculate the drive torque. Multiply the measured drive torque by a safety factor of 2 to 3 to get the design drive torque.

Now calculate the power to run the conveyor from the design drive torque and RPM (45.5 RPM). After the torque and power are well understood, then we can start to size the motor and reducer.
Thank you so much!

I will look into this as soon as possible and try to keep you guys updated with any progress,

Thank you to everyone who has contributed and helped out it really means a lot and I hope to come back with more questions or even participate in discussion myself
 
  • #33
oho11 said:
Sorry I forgot to mention that I got the 70 mm from the shaft coming out the motor, the one you have shown is the sprocket that moves the conveyor belt, I did this because @jrmichler mentioned to measure the rpm coming OUT the motor
If the sprocket that moves the conveyor is 702mm this changes everything.
 
  • #34
Devin-M said:
If the sprocket that moves the conveyor is 702mm this changes everything.
I have shows how the system goes from the motor, to a sprocket moving another sprocket with the same amount of teeth, which moves that bigger sprocket. I just want to know if the motor I have specified is enough for my use, if not I will need a bigger motor obviously.

The reason for my post is that I don't really understand how torques and forces are transferred in a sprocket system, when you say it changes everything what do you mean exactly?
 
  • #35
oho11 said:
The reason for my post is that I don't really understand how torques and forces are transferred in a sprocket system, when you say it changes everything what do you mean exactly?
If the sprocket that moves the conveyor is 702mm instead of 70mm, the motor will need to turn 10x slower and output 10x as much torque.
 
  • #36
Devin-M said:
If the sprocket that moves the conveyor is 702mm instead of 70mm, the motor will need to turn 10x slower and output 10x as much torque.
So logically speaking motor wouldn't be enough right? Since as I mentioned the 70 mm is the shaft coming out the motor which turns the sprocket that is 234 mm, the 234 mm sprocket turns another 234 mm sprocket which is connected to the 702 mm you mentioned by a shaft (as shown in my drawing), so now what I get is that I need a motor with a low rpm and a high torque?
 
  • #37
oho11 said:
so now what I get is that I need a motor with a low rpm and a high torque?
Or a greater reduction ratio in the gearbox.
 
  • #38
Baluncore said:
Or a greater reduction ratio in the gearbox.
So instead of 137:1 it would need to be more than 137 right?
 
  • #39
1370:1
 
  • #40
There is still too much possible miscommunication in this design.
I would draw a diagram of the system, showing all the stages.
Make sure all the parameters were identified for each stage.
Then recompute it for the known values.
 
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  • #41
Do you have a Machinery's Handbook? If not, I highly recommend you get one. It has virtually every thing you would need to know about any sort of mechanical application. A truly invaluable resource. We refer to it as the Bible in my industry. The standard version is nice and compact, but the larger version is easier to read.

https://books.industrialpress.com/machinery-handbook/
 
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  • #42
oho11 said:
Thank you so much I will definitely look into this as I didn't think about this part!

But how would I be able to apply this to my problem after I find the motor constant?
Rapistan Demag are the pros at this. I used to be a conveyor mechanic at a distribution center with 30 miles of conveyor belts. Once you find your max load allowance don't forget a overcurrent circuit to shutoff motor.
 
  • #43
MillGuy said:
Do you have a Machinery's Handbook? If not, I highly recommend you get one. It has virtually every thing you would need to know about any sort of mechanical application. A truly invaluable resource. We refer to it as the Bible in my industry. The standard version is nice and compact, but the larger version is easier to read.

https://books.industrialpress.com/machinery-handbook/
I used to work on Rapistan Demag systems. Pretty straight forward. He can get specs he needs for loads required
 
  • #44
oho11 said:
So logically speaking motor wouldn't be enough right? Since as I mentioned the 70 mm is the shaft coming out the motor which turns the sprocket that is 234 mm, the 234 mm sprocket turns another 234 mm sprocket which is connected to the 702 mm you mentioned by a shaft (as shown in my drawing), so now what I get is that I need a motor with a low rpm and a high torque?
A transmission gearbox
 

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