Evaluating Partial Derivative of g w.r.t. Theta at (2*sqrt(2),pi/4)

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SUMMARY

The discussion focuses on evaluating the partial derivative of the function g(x, y) = 1/(x + y²) with respect to theta at the point (r, theta) = (2√2, π/4). The chain rule is employed to compute this derivative, utilizing the transformations x = r cos(theta) and y = r sin(theta). The challenge arises from the application of polar coordinates in the context of partial derivatives, specifically in substituting x and y in the equation.

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use chain rule to evaluate partial derivative of g with respect to theta at (r,[theta])=(2*sqrt(2),pi/4), where g(x,y) = 1/(x+y^2), x=rsin[theta] and y=rcos[theta]


r^2=x^2+y^2 and tan[theta]=y/x

The Attempt at a Solution



I understand how to use the chain rule for partial derivatives, but I can't seem to figure out any of the problems that use polar coordinates. please help.
 
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use
x=rcos(theta)
y=rsin(theta)
 
m_s_a said:
use
x=rcos(theta)
y=rsin(theta)

- so for every x/y in the equation I get, plug in the polar coordinate for them?
 

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